InterviewSolution
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A Force →F=(6^i+4^j−2^k) N is applied on a block which is moving with velocity →v=(8^i+12^j−3^k) m/s. The instantaneous power applied to the particle is |
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Answer» A Force →F=(6^i+4^j−2^k) N is applied on a block which is moving with velocity →v=(8^i+12^j−3^k) m/s. The instantaneous power applied to the particle is |
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