InterviewSolution
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InterviewSolution
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A force F=a+bx acts on a particle in the x-directioin, where a and b are constants. Find the work done by this force during a displacement form `x=0 to x=d`. |
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Answer» Correct Answer - A::B::D Given that `F=a+bx` Where a and b are constants So, work done by this force during the displacement x=0 to x=d is given by `W=int_0^d Fdx ` `int_0^d(a+bx)dx` `=[ax+(bx^2)/2]_0^d` `=ad+(bd^2)/2` |
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