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A force F=(a+bx) acts on a particle in x direction where a and b are constants . Find the work done by this force during displacement from `x_(1)` to `x_(2)` . |
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Answer» Work done for displacement dx `dW=Fdx=(a+bx)dx` Total work done `W= int dW` `=int_(x_(1))^(x_(2))(a+bx)dx` `=[ax+(bx^(2))/(2)]_(x_(1))^(x_(2))` ` =a(x_(2)-x_(1))+(b)/(2)(x_(2)^(2) -x_(1)^(2))` |
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