1.

A force F appllied to a body(A)of mas m_(1) produces an acceleratioin of 4m//s^(2). If the same force F is applied to another body (B) of mass m_(2), then an acceleratiionof 10m//s^(2), produced in the body. A and B are the tied together and the same force is applied to the combined body. What is the acceleration of the system?

Answer»

`10/7m//s^(2)`
`20/7m//s^(2)`
`5/3m//s^(2)`
`7/20m//s^(2)`

Solution :`because F= m xxa therefore m_(1) = (F)/(4) and m_(2)= (F)/(10)`
and the COMBINEDMASS (M) `=m_(1)+m_(2)`
`=(F)/(4)+(F)/(10)= (14F)/(40)`
`therefore` Acceleration of the system `= (F)/(M)= (F)/(14F//40)`
`=(40)/(14)= (20)/(7) m//s^(2)`


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