A force F is applied at the top of a ring of mass M and radius R placed on a rough horizontal surface. Friction is sufficient to prevent slipping. Find the frictional force acting on the ring.

A force F is applied at the top of a ring of mass M and radius R place

1.	A force F is applied at the top of a ring of mass M and radius R placed on a rough horizontal surface. Friction is sufficient to prevent slipping. Find the frictional force acting on the ring.
Answer» Solution :`ALPHA=(TAU)/(I)=(F(2R))/(2MR^(2))=(F)/(MR)` Now `F+f=Ma=MRalpha` = F or f=0