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A force F is given by F = at + bt^(2), where t is time. The dimensions of a and b are |
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Answer» `[MLT^(-3)]` and `[MLT^(-4)]` `[a]= ([F])/([t])= ([MLT^(-2)])/([T])= [MLT^(-3)]` `[b]=([F])/([t^(2)])= ([MLT^(-2)])/([T^(2)])= [MLT^(-4)]` |
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