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A force F is given by F = at + bt^(2), where t is time. The dimensions of a and b are |
Answer» <html><body><p>`[MLT^(-3)]` and `[MLT^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)]`<br/>`[MLT^(-4)]` and `[MLT^(-3)]`<br/>`[MLT^(-1)]` and `[MLT^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)]`<br/>`[MLT^(-2)]` and `[MLT^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)]`</p>Solution :From `<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>= at+bt^(2)` <br/> `[a]= ([F])/([t])= ([MLT^(-2)])/([T])= [MLT^(-3)]` <br/> `[b]=([F])/([t^(2)])= ([MLT^(-2)])/([T^(2)])= [MLT^(-4)]`</body></html> | |