1.

A force F is given by F = at + bt^(2), where t is time. The dimensions of a and b are

Answer»

`[MLT^(-3)]` and `[MLT^(-4)]`
`[MLT^(-4)]` and `[MLT^(-3)]`
`[MLT^(-1)]` and `[MLT^(-2)]`
`[MLT^(-2)]` and `[MLT^(0)]`

Solution :From `F= at+bt^(2)`
`[a]= ([F])/([t])= ([MLT^(-2)])/([T])= [MLT^(-3)]`
`[b]=([F])/([t^(2)])= ([MLT^(-2)])/([T^(2)])= [MLT^(-4)]`


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