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A force `F` is given by `F = at + bt^(2)` , where `t` is time . What are the dimensions of `a and b`? |
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Answer» From the principle of dimensional homogenity , `[ F] = [ at]` :. ` [ a] = [(F)/(t) ] = [ (MLT^(-2))/( T)] = [ MLT^(-3)` Similarly ,`[F] = [ bt^(2)]` :. `[b] = [(F)/(t^(2))] = [ (MLT^(-2))/( T^(2))] = [ MLT^(-4)]` |
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