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| 1. |
A force F is given byF=at+bt^2 where t is time. What are the, dimensions of a and b? |
| Answer» SOLUTION :`[F]=[at]=[bt^2][a]=[[F]]/[[t]]=[[MLT^2]]/[[T]]=[MLT^-3][B]=[[F]]/[[t^2]]=[[MLT^2]]/[[T^2]]=[MLT^-4]` | |