A force F is related to the position of a particle by the relation F = (10x^2) N. The work done by the force when the particle moves from x= 2 m to x = 4 m is

A force F is related to the position of a particle by the relation F =

1.	A force F is related to the position of a particle by the relation F = (10x^2) N. The work done by the force when the particle moves from x= 2 m to x = 4 m is
Answer» <html><body><p>`56/<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`<br/>`560J`<br/>`560/3 J`<br/>`3/560 J`</p>Solution :`W = int_2^<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> F dx = int_2^4 <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> x^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> dx = [(10 x^3)/(3)]_(2)^(4)` <br/> `= 10/3 [4^3 - 2^3] = 10/3 xx 56 = 560/3 J`</body></html>