A force F=−k(yi+xj) (where k is a positive constant) acts on a particle moving in the xy - plane. Starting from the origin, the particle is taken along the positive x - axis to the point (a,0) and then parallel to the y - axis to the point (a,a). The total work done by the force F on the particle is

A force F=−k(yi+xj) (where k is a positive constant) acts on a parti

1.	A force F=−k(yi+xj) (where k is a positive constant) acts on a particle moving in the xy - plane. Starting from the origin, the particle is taken along the positive x - axis to the point (a,0) and then parallel to the y - axis to the point (a,a). The total work done by the force F on the particle is
Answer» A force $F = - k (y i + x j)$ (where $k$ is a positive constant) acts on a particle moving in the $x y$ - plane. Starting from the origin, the particle is taken along the positive $x$ - axis to the point $(a, 0)$ and then parallel to the $y$ - axis to the point $(a, a)$ . The total work done by the force $F$ on the particle is

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