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A force F=−kx2(x≠0) acts on a particle in x−direction. Find the work done by this force in displacing the particle from x=+a to x=+2a. Here k is a positive constant.

Answer»

A force F=kx2(x0) acts on a particle in xdirection. Find the work done by this force in displacing the particle from x=+a to x=+2a. Here k is a positive constant.



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