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A force is given by `F= at + bt^(2) ` where , t is the time .The dimensione of a and b areA. `[M^(1)L^(1)T^(3)],[M^(1)L^(1)T^(-4)]`B. `[M^(2)L^(1)T^(2)],[M^(1)L^(1)T^(-2)]`C. `[M^(1)L^(-1)T^(-2)],[M^(1)L^(2)T^(-3)]`D. `[M^(-1)L^(1)T^(-4)],[M^(1)L^(1)T^(-3)]` |
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Answer» Correct Answer - A In a dimensional equation, all terms must have the same dimensions. In this case, they should have the dimensions of force. `[F]=[M^(1)L^(1)T^(-2)]` (i) `[a]=[(F)/(t)]=[(M^(1)L^(1)T^(-2))/(T^(1))]=[M^(1)L^(1)T^(-3)]` (ii) `[b]=[(F)/(t^(2))]=[(M^(1)L^(1)T^(-2))/(T^(2))]=[M^(1)L^(1)T^(-4)]` |
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