1.

A force of 0.12 newton for 3 second and body mass 0.4 kg of rest If the velocity gain by the body.

Answer»

f = ma, u = 0

\(f = m\frac{(v-u)}{t}\)

f x t = m (v)

\(\frac{f \times t}{m} = v\)

\(\frac{f \times t}{m} = \frac{0.12 \times 3}{0.4}\) = 9

v = 9 m/s.



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