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A force of 0.12 newton for 3 second and body mass 0.4 kg of rest If the velocity gain by the body. |
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Answer» f = ma, u = 0 \(f = m\frac{(v-u)}{t}\) f x t = m (v) \(\frac{f \times t}{m} = v\) \(\frac{f \times t}{m} = \frac{0.12 \times 3}{0.4}\) = 9 v = 9 m/s. |
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