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A force of 10 N acts on a body of mass 1.0 kg at rest. Find the work done in 4 seconds. |
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Answer» SOLUTION :F = 10 N,m = 1.0 kg , u = 0, t = 4s, acceleration `a = (F)/(m) xx (10)/(1) = 10MS^(-1)`. Its displacement `S=ut+(1)/(2)at^(2)=0+(1)/(2)(10)4^(2)=80m` The work done W = FS = MAS = `1.0 xx 10 xx 80 = 800j` |
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