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A force of 100 N increases the length of a given wiere by 0.1 mm. Then the force required to increase its length by 0.25 mm isA. 50 NB. 150 NC. 250 ND. 500 N |
Answer» Correct Answer - C `(F_(2))/(F_(1))=(l_(2))/(l_(1))=(0.25)/(0.10)=(5)/(2)` `F_(2)=(5)/(2) xx F_(1)` `=(5)/(2)xx100 = 250N` |
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