A force of (2hati+3hatj+5hatk)N is is applied at a point whose position vector is(7hati+4hatj-2hatk)m. Find thetorque of force about the origin.

A force of (2hati+3hatj+5hatk)N is is applied at a point whose positio

1.	A force of (2hati+3hatj+5hatk)N is is applied at a point whose position vector is(7hati+4hatj-2hatk)m. Find thetorque of force about the origin.
Answer» SOLUTION :`vecr=7 hati+4hatj-2hatk` `vecF=4hati-3hatj+5hatk` TORQUE, `VEC tau= vec r XX vec F` `vectau=\|{:(hati, hatj, hatk),(7,4,-2),(4,-3,5):}\|` `tau=hati(20-6)-hatj(35+8)+hatk(-21-16)` `tau=(14hati-43hatk-37hatk) Nm`