A force of 45 N acts on a body and moves it a distance of 3m on a horizontal surface. Calculate the work done if the direction of force is at an angle of 60° to the horizontal surface. Derive the relation between kWh and joule.

A force of 45 N acts on a body and moves it a distance of 3m on a hori

1.	A force of 45 N acts on a body and moves it a distance of 3m on a horizontal surface. Calculate the work done if the direction of force is at an angle of 60° to the horizontal surface. Derive the relation between kWh and joule.
Answer» tion:Force acting on the body = 10 kgf = 10 x 10 N = 100 NDisplacement, S=0.5 mWork done= force x displacement in the direction of force(i)W =F x SW = 100 x 0.5= 50 J(ii)WORK = force x displacement in the direction of forceW = F x S cosW = 100 x 0.5 cos60oW= 100 x0.5 x 0.5(cos60o=0.5)W=25 J(iii)NORMAL to the force:Work = force x displacement in the direction of forceW = F x S cosW = 100 x 0.5 cos90oW= 100 x 0.5 x 0 =0 J(cos90o =0)

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A force of 45 N acts on a body and moves it a distance of 3m on a horizontal surface. Calculate the work done if the direction of force is at an angle of 60° to the horizontal surface. Derive the relation between kWh and joule.​

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A force of 45 N acts on a body and moves it a distance of 3m on a horizontal surface. Calculate the work done if the direction of force is at an angle of 60° to the horizontal surface. Derive the relation between kWh and joule.