A force of 5 xx 10^(3) N is applied tangentially to the upper face of a cubical block of steel of side 30 cm. Find the displacement of the upper face relative to the lower one, and the angle of shear. The shear modulus of steel is 8.3 xx 10^(10) pa.

A force of 5 xx 10^(3) N is applied tangentially to the upper face of

1.	A force of 5 xx 10^(3) N is applied tangentially to the upper face of a cubical block of steel of side 30 cm. Find the displacement of the upper face relative to the lower one, and the angle of shear. The shear modulus of steel is 8.3 xx 10^(10) pa.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Area A of the upper face = `(0.30)^(2) m^(2)` <br/> The displacement `Deltax` of the upper face relative to the lower one is given by <br/> `Deltax=(<a href="https://interviewquestions.tuteehub.com/tag/yf-749487" style="font-weight:bold;" target="_blank" title="Click to know more about YF">YF</a>)/(etaA), :.eta=(F/A)/(Deltax//y)` <br/> `(0.30xx5xx10^(3))/(8.3xx10^(10)xx(0.30)^(2))=2xx10^(-7)` m <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/DBT_SM_PHY_XI_U_07_E05_003_S01.png" width="80%"/> <br/> `:.` <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> of shear `alpha ` is given by <br/> <a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a>`alpha= (Deltax)/(y)` <br/> `alpha=tan^(-1)((Deltax)/(y))` <br/> = `tan^(-1)((2xx10^(-7))/(0.30))=tan^(-1)(0.67xx10^(-6))`</body></html>