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A force of 50 N is applied normally on a table of area 2 N/m2.Then the pressure exerted on the table is: 25N/m250N/m210 N/m2100N/m2other. plz Answer to this plz.Now I am in online test plz |
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Answer» 50 N AREA = 2 m²Pressure = Force / Area==> Pressure = 50/2==> Pressure = 25 Pa |
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