Saved Bookmarks
| 1. |
A force of 50 Nact on the object of mass 20 kg calculate the acceleration of the object in x and y direction |
Answer» Solution : Given F = 50N and m= 20 KG (i) component of force along x-direction `F_x = F COS theta` `= 50 xx cos 30^@ = 43.30 N` ` therefore a_x = (F_x)/(m)= (43.30)/(20) = 2.165 MS^(-2)` (ii) Component of force along y-direction ` F_y = F sin theta = 50 xx sin 30^@ = 25N` ` therefore a_y = (F_y)/(m) = 25/20 = 1.25 ms^(-2)` |
|