1.

A force of 5N acts on a particle along a direction making an angle of 30^(@)with vertical . Its vertical component will be :

Answer»

10N
3N
4N
2.5N

Solution :`F = 5N, theta = 30^(@)`
`F sin theta = 5 sin 30^(@)``= 5 XX (1)/(2) = 2.5 N`


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