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A force of 72 dyne is inclined to the horizontal at an angle of 60°. Find the acceleration in a mass of 9 g, which moves in a horizontal direction. |
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Answer» Component of force along horizontal, Fx = F cos 60° = 72 x \(\frac{1}{2}\) = 36 dyne Using, Fx = max we get, ax = \(\frac{F_x}{m} = \frac{36}{9}\) = 4 cms-2 |
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