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A force of 98 N is just required to move a mass of 45 kg on a rough horizontal surface. Find the coefficient of friction and angle of friction? |
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Answer» SOLUTION : `F= 48 N, R = 45 xx 9.8 = 441 N` ` mu = (F.)/(R ) = 0.22` ANGLE of friction ` theta = TAN^(-1) mu= tan^(-1) 0.22 =12^@ 24.` |
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