Saved Bookmarks
| 1. |
A force of constant magnitude F acts on a particle moving in a plane such that it is perpendicular to the velocity `vecv(|vecv|=v)` of the body and the force is always direct towards a fixed point. Then the angle turned by the velocity vector of the particle as it covers a distance S is (take mass of the particle as m)A. `(FS)/(2mv^(2))`B. `(2FS)/(mv^(2))`C. `(FS^(2))/(mv)`D. `(FS)/(mv^(2))` |
|
Answer» Since `vecFbotvecV` the particle will move along a circle `thereforeF=(mv^(2))/(R)&theta=(S)/(R)impliestheta=(FS)/(mv^(2))` |
|