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A force of `-Fhatk` acts on O, the origin of the coodinate system. The torque about the point (1,-1) is A. `-F(hati+hatj)`B. `F(hati+hatj)`C. `-F(hati-hatj)`D. `F(hati-hatj)` |
Answer» `vecr=hati-hatj`, `vecF= -Fhatk` `vectau=vecrxxvecF=(hati-hatj)xx(-Fhatk)` `= -F[hatixxhatk-hatjxxhatk]` `= -F[-hatj-hati]=F[hati+hatj]` |
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