A force of magnitude 12 N acts on a particle in the direction of a vector →A=2^i−4^j+4^k, which results in the change of position of the particle from (3,3,5) m to (2,−1,4) m. The work done by the force is (in Joule )

A force of magnitude 12 N acts on a particle in the direction of a vec

1.	A force of magnitude 12 N acts on a particle in the direction of a vector →A=2^i−4^j+4^k, which results in the change of position of the particle from (3,3,5) m to (2,−1,4) m. The work done by the force is (in Joule )
Answer» A force of magnitude $12 N$ acts on a particle in the direction of a vector $\to A = 2^i - 4^j + 4^k$ , which results in the change of position of the particle from $(3, 3, 5) m$ to $(2, - 1, 4) m$ . The work done by the force is (in Joule )

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A force of magnitude 12 N acts on a particle in the direction of a vector →A=2^i−4^j+4^k, which results in the change of position of the particle from (3,3,5) m to (2,−1,4) m. The work done by the force is (in Joule )

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