A force of vecF = (4hati-3hatj+5hatk)N is applied at a point whose position vector is vec r = (7hati+4hatj-2hatk)m. Find the torque of force about the origin.

A force of vecF = (4hati-3hatj+5hatk)N is applied at a point whose pos

1.	A force of vecF = (4hati-3hatj+5hatk)N is applied at a point whose position vector is vec r = (7hati+4hatj-2hatk)m. Find the torque of force about the origin.
Answer» Solution :`vecr = 7hati + 4hatj - 2HATK` `VECF = 4hati - 3hatj + 5hatk` TORQUE , `vectau = vecr xx vecF` `vectau = \|{:(hati , HATJ , HATK),(7,4,-2),(4,-3,5):}\|` `vectau = hati (20-6) -hatj(35+8) + hatk (-21-16)` `vectau = (14hati - 43 hatj - 37 hatk)`Nm