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A force `vec(F) == b (-y hat(i) + x hat(j))/(x^(2) + y^(2)) N` (b is a constant) acts on a particle as it undergoes counterclock-wise circular motion in a circle : `x^(2) + y^(2) = 16`. The work done (in J) by the force when the particle undergoes one complete revolution is (x, y are in m)A. ZeroB. `2 pi b`C. `2b`D. None of these |
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Answer» Correct Answer - B `W = oint vec(F) .d vec(r)` `= oint (bd vec(r))/(|d vec(r)|R).d vec(r)` `= (b)/(R) oint |d vec(r)| = (2 pi Rb)/(R) = 2 pi bJ` |
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