1.

A frustum has been mounted with its axis vertical. It has a height h and radii of its upper and lower cross sections are R and r respectively. A particle is projected with horizontal velocity v_(0) along its upper brim. The particle spirals down the inner surface and leaves the lower face at point B. The inner wall of the frustum is smooth. (a) Find the vertical component of velocity of the particle as it leaves the frustum at B. (b) Find minimum value of h for which theparticle will never come out of the frustum. Take r = (R)/(2)for solving this part of the problem.

Answer»


ANSWER :(a) `SQRT(2gh - v_(0)^(2) ((R^(2))/(r^(2)) - 1))`
(b) `h_("min") = sqrt((3)/(2g))v_(0)`


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