1.

A fuel cell generates a standard electrode potential of 0.7 V, involving 2 electrons in its cell reaction. Calculate the standard free energy change for the reaction. "Given F= 96487 C mol"^(-1).

Answer»

Solution :STANDARD free energy CHANGE for the reaction
`DeltaG^(@)=-nFE^(@)`
`"Given : "E^(@)=0.7V, n=2, F="96500 C MOL"^(-1)`
`DeltaG^(@)=-2xx96500xx0.7V`
`=-135100 J`
`=-135kJ`


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