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A function f:R→R+ satisfies f(x+y)=f(x)f(y) ∀ x,yϵR. If f′(0)=2 then∀x,yϵR, f′(x)= |
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Answer» A function f:R→R+ satisfies f(x+y)=f(x)f(y) ∀ x,yϵR. If f′(0)=2 then∀x,yϵR, f′(x)= |
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