A function f(theta) is defined as f(theta)=1-theta+(theta^(2))/(2!)-(theta^(3))/(3!)+(theta^(4))/(4!) +.... Why is it necessary for f(theta) to be a dimesnionless quantity ?

A function f(theta) is defined as f(theta)=1-theta+(theta^(2))/(2!)-(t

1.	A function f(theta) is defined as f(theta)=1-theta+(theta^(2))/(2!)-(theta^(3))/(3!)+(theta^(4))/(4!) +.... Why is it necessary for f(theta) to be a dimesnionless quantity ?
Answer» SOLUTION :Since, `f (theta)` is a sum of different power of `theta` and as RHS is dimensionless, HENCE LHS should also be dimensionless.