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A function y=f(x) satisfies the equation f(x+y)=f(x)⋅f(y) where x,y∈R. It is known that f(1)=25. If S=f(2)+f(1)+f(0)+f(−1)+...∞, then the value of [(f(1)−1)S]1/2 is |
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Answer» A function y=f(x) satisfies the equation f(x+y)=f(x)⋅f(y) where x,y∈R. It is known that f(1)=25. If S=f(2)+f(1)+f(0)+f(−1)+...∞, then the value of [(f(1)−1)S]1/2 is |
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