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A function y=f(x) satisfies (x+1)f′(x)−2(x2+x)f(x)=ex2(x+1),∀ x>−1.If f(0)=5, then the function f(x) is obtained as: |
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Answer» A function y=f(x) satisfies (x+1)f′(x)−2(x2+x)f(x)=ex2(x+1),∀ x>−1. |
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