1.

A function y=f(x) satisfies xf′(x)−2f(x)=x4f2(x), ∀ x>0 and f(1)=−6. Then the value of f′(31/5) is

Answer» A function y=f(x) satisfies xf(x)2f(x)=x4f2(x), x>0 and f(1)=6. Then the value of f(31/5) is


Discussion

No Comment Found