A g of a metal displaces VmL of H_(2) at NTP Eq.wt. of metal, E is (ar

1.	A g of a metal displaces VmL of H_(2) at NTP Eq.wt. of metal, E is (are):
Answer» `E=(Axx1.008xx22400)/("Vol.of" H_(2)"displaced"xx2)` `E=(AxxEq."mass .of"H)/("mass of"H_(2)"displaced")` `E=(Axx1.008)/("Vol.of displaced"xx0.000897)` None of these Answer :A::B::C

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