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`{:(A^(-) (g) rarr A^(2+)(g),,DeltaH = 1100KJ//mol),(A(g)rarrA^(2+)(g),,DeltaH = 1200 KJ//mol):}` Electron gain enthalpy of `A` is `P xx 10^(2) KJ//mol`. What is the value of `P`? |
Answer» Correct Answer - 1 `A(g) +e^(-) rarr A^(-)(g) DeltaH = + E.G.E ….(1)` `A(g) rarr A^(2+) (g)+2e^(-) DeltaH = 1200 KJ//mol ……..(2)` `A^(-)(g) rarr A^(2+)(g)+3e^(-) DeltaH = 1100 KJ//mol ……(3)` `Eq.(3) = (2) - (1)` `- E.G.E +1200 = 1100` `-E.G.E =- 100 kJ//mol` `P = 1`. |
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