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A galvanic cell consists of a metallic zinc plate immersed in 0.1 M Zn(NO_(3))_(2) solution. Calculate the emf of the cell at 25^(@)C. Write the chemical equations for the electrode reactions and represent the cell. (Given : E_(Zn^(2+)//Zn)^(@) = - 0.76 volt and E_(Pb^(2+)//Pb)^(@) = - 0.13 volt)

Answer»


Answer :`ZN rarr Zn^(2+) + 2e^(-),""Pb^(2+)+2e^(-) rarr Pb`
`Zn|underset(0.1 M)(Zn^(2+))||underset(0.02 M)(Pb^(2+))|Pb`
`E_(cell)^(@)=0.63" VOLT"E_(cell)=0.609" volt"`


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