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A galvanic cell is set up from a zinc bar weighing `100g` and `1.0L` of `1.0M CuSO_(4)` solution. How long would the cell run if it is assumed to deliver a steady current of `1.0A. (` Atomic mass of `Zn=65)`.A. `1.1` hoursB. 46 hoursC. `53.6` hourseD. 24 hours. |
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Answer» Correct Answer - c Mole of `Zn=(100)/(65.3)=1.53mol` Mole of `Cu^(2+)=1xx1=1 mol ` So `Zn` is in excess, hence `Cu^(2+)` will react completely. `Cu^(2+)+2e^(-) rarr Cu` `2F-=1 mol `of `Cu` `2xx96500C-=1.0Axxt(` in seconds `)` `t=(2xx96500)/(3600)h=53.6h` |
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