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A galvanometer coil has a resistance `90 Omega` and full scale deflection current `10 mA`. A `910 Omega` resistance is connected in series with the galvanometer to make a voltmeter. If the least count of the voltmeter is `0.1 V` the number of divisions on its scale isA. 90B. 91C. 100D. None |
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Answer» Correct Answer - C (c ) `R_(v) = (V)/(i_(g)) - G implies 910 = (V)/(10 xx 10^(-3)) = 90` `implies V = 10 implies` No. of division `= (10)/(0.12) = 100` |
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