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A galvanometer coil has a resistance of `12Omega` and the meter shows full scale deflection for a current of `3mA`. How will you convert the meter into a voltmeter of range 0 to 18V? |
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Answer» Here, `G=12Omega`, `I_g=3mA=3xx10^-3A`, `V=18V`, `R=?` From, `R=(V)/(I_g)-G=(18)/(3xx10^-3)-12=6000-12=5988Omega` This resistance is to be connected in series with the galvanometer. |
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