1.

A galvanometer coil has a resistance of `12Omega` and the meter shows full scale deflection for a current of `3mA`. How will you convert the meter into a voltmeter of range 0 to 18V?

Answer» Here, `G=12Omega`, `I_g=3mA=3xx10^-3A`, `V=18V`, `R=?`
From, `R=(V)/(I_g)-G=(18)/(3xx10^-3)-12=6000-12=5988Omega`
This resistance is to be connected in series with the galvanometer.


Discussion

No Comment Found

Related InterviewSolutions