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A galvanometer has a resistance of `25 ohm` and a maximum of `0.01 A` current can be passed throught it. In order to change it into an ammeter of range `10 A`, the shunt resistance required isA. `5//999 ohm`B. `10//999 ohm`C. `20//999 ohm`D. `25//999 ohm` |
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Answer» Correct Answer - D (d) `i_(g) = i(S)/(G + S) implies 0.01 = 10 (S)/(24 + S)` `implies 1000 S = 25 + S implies S = (25)/(999) Omega` |
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