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A galvanometer having a coil resistance of `60 Omega` shows full scale defection when a current of `1.0 A` passes thoguth it. It can vbe convered into an ammeter to read currents up to `5.0 A` byA. putting in parallel a resistance of `240 Omega`B. putting in series a resistance of `15 Omega`C. putting in series a resistance of `240 Omega`D. putting in parallel a resistance of `15 Omega` |
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Answer» Correct Answer - D To convert a galbonmeter to ammeter to ammrter a small resistance is connected in parallel to the coil of the galvanometer.n Here, `G_(1) = 60 Omega I_(g) = 1.0 A, I = 5A` `I_(R) G_(1) = (1 - 1_(g))S` `S = (I_(g) G_(1))/(I - I_(g)) = (1)/(5 - 1) xx 60 = 15 Omega` Putting `15 Omega` resistance in parallel. |
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