1.

A galvanometer of resistance `20Omega` is to be shunted so that only `1%` of the current passes through it. Shunt connected is `99//20Omega`A. `9//20Omega`B. `20//99Omega`C. `2//99Omega`D.

Answer» Correct Answer - 3
`S=(G)/((i)/(i_(g))-1)`


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