1.

A galvanometer with `50` divisions on the scale has a resistance of `25 Omega`. A current of `2 xx 10^-4` A gives a deflection of one scale division. The additional series required to convert it into a voltmeter reading up to `25 V` is.A. `1200 Omega`B. `1225 Omega`C. `2475 Omega`D. `2500 Omega`

Answer» Correct Answer - C
`i_g = 50 xx 2 xx 10^-4 = 10^-2 A, G = 25 Omega`
`V = i_g(R + G)`
`25 = 10^-2(R + 25) rArr R = 2475 Omega`.


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