1.

A gardener increased the area of his rectangular garden by increasing its length by 40% and decreasing its width by 20%. The area of the new garden1. has increased by 20%2. has increased by 12%3. has increased by 8%4. is exactly the same as the old area.

Answer» Correct Answer - Option 2 : has increased by 12%

Given:

Increment in length = 40%

Decrement in width = 20%

Formula Used: 

Area of rectangle = l × b

Where, l = length, b = width

Calculation:

Let the length and width of a rectangular garden be l and b respectively

⇒ The old area of rectangle = l × b

According to the question, we have

The new area of garden = l × (140/100) × b × (80/100) 

⇒ (28/25)(lb)

The percentage increments in area of the garden = \(\left[ {\frac{{\frac{{28}}{{25}}\left( {{\rm{lb}}} \right)~-~\left( {{\rm{lb}}} \right)}}{{\left( {{\rm{lb}}} \right)}}} \right] \times 100\)

⇒ 3 × 4

⇒ 12%

∴ The area of the garden increased by 12%.


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