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A gardener is watering plants at the rate 0.1 litre/sec using a pipe of cross - section 1 cm^(2). What additional force he has to exert if he desires to increasethe rate of watering two times ?

Answer» <html><body><p></p>Solution :`F=Adv^(2)=((Av)^(2)d)/(A)` If rate of watering plant (Av) is doubled, it means amount of water poured / sec is doubled which is possible only if velocity is doubled. Hence force is to be made 4 <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a>.<br/>`<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` additional force = 3 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> initial force<br/>`= 3Adv^(2)=3((Av)^(2))/(A)d`<br/>`= (3xx0.1xx0.1xx10^(3))/(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-4))=3xx10^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)N`</body></html>


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