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A gas consisting of rigid diatomic molecules (degrees of freedom r = 5) under standard conditions `(P_(0) = 10^(5)` Pa and `T_(0) = 273 K`) was compressed adiabatically `eta = 5` times. Find the mean kinetic energy of a rotating molecule in the final state. |
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Answer» In an adiabatic expansion, `TV^(gamma-1)=` constant `T_(0)V^(gamma-1)=T((V)/(5))^(gamma-1) gamma=1+(2)/(5)` `therefore T=(273).(5)^(2//5)` `lt(KE)_("rotational")gt` `= kT` `=1.38xx10^(-23)xx273xx(5)^(2//5)` `=7xx10^(-21)J` (approx). |
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