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A gas cylinder containing cooking gas can withsand a pressure of 14.9 atmosphere. The pressure gauge of the cylinder indicates 12 atmosphere at `27^(@)C`. Due to a sudden fire in the building the temperature starts rising. At what temperature will the cylinder explode ? |
Answer» Since, the gas is confined in a cylinder, its volume will remain constant `{:("Initial conditions","Final conditions",),(P_(1) = 12 atm,P_(2) = 14.9 atm,),(T_(1) = 27 + 273 = 300 K,T_(2) = ?,):}` Applying pressure - temperature law, `(P_(1))/(T_(1)) = (P_(2))/(T_(2))` So, `T_(2) = (P_(2) xx T_(1))/(P_(1)) = (14.9 xx 300)/(12) = 372.5 K` Temperature in `.^(@)C = (372.5 - 273) = 99.5^(@)C` |
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