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A gas cylinder contains oxygen gas at 25^@C and 15.0 atm. If the temperature of the surroundings rises to 42^@C, whatwould be the pressure of the gas in the cylinder ? |
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Answer» Solution :In the present CASE, `P_1 = 15.0 " atm,"T_1 = 25^@C = 25 + 273 = 298 K, P_2 = ?, T_2 = 42^@C = 42 + 273 = 315 K` Using the pressure-temperature law `P_1/T_1 = P_2/T_2`and substituting the values, we get `P_2 = (P_1T_2)/(T_1) = (15.0 x 315)/(298) = 15.86` atm |
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