A gas cylinder contains oxygen gas at 25^@C and 15.0 atm. If the temperature of the surroundings rises to 42^@C, whatwould be the pressure of the gas in the cylinder ?

A gas cylinder contains oxygen gas at 25^@C and 15.0 atm. If the tempe

1.	A gas cylinder contains oxygen gas at 25^@C and 15.0 atm. If the temperature of the surroundings rises to 42^@C, whatwould be the pressure of the gas in the cylinder ?
Answer» <html><body><p></p>Solution :In the present <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a>, <br/> `P_1 = 15.0 " atm,"T_1 = 25^@<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> = 25 + <a href="https://interviewquestions.tuteehub.com/tag/273-1832932" style="font-weight:bold;" target="_blank" title="Click to know more about 273">273</a> = 298 <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>, P_2 = ?, T_2 = <a href="https://interviewquestions.tuteehub.com/tag/42-316129" style="font-weight:bold;" target="_blank" title="Click to know more about 42">42</a>^@C = 42 + 273 = 315 K` <br/> Using the pressure-temperature law `P_1/T_1 = P_2/T_2`and substituting the values, we get <br/> `P_2 = (P_1T_2)/(T_1) = (15.0 x 315)/(298) = 15.86` atm</body></html>